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Project 1 Sampling Rate Conversion 

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Sampling Rate Conversion

Overview

In discrete‐time signal processing, it is often necessary to convert a signal from one sampling rate to
another. A common example is the conversion from the sampling rate of a compact disk (CD); signal
(44.1 KHz) to that of a Digital Audio Tape (DAT) signal (48 KHz).

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Sampling Rate Conversion
Overview
In discrete‐time signal processing, it is often necessary to convert a signal from one sampling rate to
another. A common example is the conversion from the sampling rate of a compact disk (CD); signal
(44.1 KHz) to that of a Digital Audio Tape (DAT) signal (48 KHz). Another example is the aud io standard
in High‐Definition Television (HDTV) transmission, where at least three sampling rates are supported
(32, 44.1, and 48 KHz). Although in principle we may convert the signal back to analog form and
resample at the desired rate, it is usually preferable to perform t he entire conversion digitally. This is
clue to many considerations including the fact that conversion to analog form often introduces noise in
the signal, and that digital signal processing can be much more cost‐effective and flexible.
This MATLAB project asks you to perform a sampling rate conversion on segments of audio signals. The
input audio signals are quantized to 8 bits and sampled with a sampling frequency of 11,025 Hz. You are
required to convert the signal to a sampling rate of 24,000 Hz in a computationally efficient manner.
Although one conceptual way of realizing this sampling rate conversion process is to upsample the
signal, lowpass filter, and downsample it, a more clever implementation can lead to an implementation
that is many times more efficient. To do this, you can exploit various aspects of class to optimize the
system, such as multistage filter implementation, filter design, and polyphase implementation. By the
end of the project, you hopefully will have a much better understanding of both the theoretical aspect
of the system as well as various issues in implementing a practical DSP system at a software level.
Project Goal
A sampling rate converter which produces an output signal with a sampling rate which is
M
L times the
original sampling rate can be specified as shown in Figure 1.
Figure 1: Sampling rate conversion system.
For an ideal sampling rate converter, the lowpass filter in Figure 1 is an ideal lowpass filter with cutoff
frequency ⎟

⎞ ⎜

⎛ = LM c
ππ
ω ,min The goal of this project is to design an efficient DSP algorithm that
implements the system in Figure 1 subject to the following constraints:
• The system performs the correct sampling rate conversion from 11,025 Hz to 24,000 Hz. In
particular, do not assume that 11,025 Hz ≈ 11,000 Hz.
x[ ] n y n[ ] Lowpass
filter
↑ L ↓ M
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If the system in Figure 1 is an ideal sampling rate converter , when the input x[n] is a unit impulse
δ n],[ the output y[n] has a Fourier transform ( ) jω eY which corresponds to an ideal lowpass filter with
a cutoff frequency at ωc = (11,025/ 24,000)π. For an equivalent system which you are to implement,
when the input x[n] is a unit impulseδ n][ , the output y[n] must have a Fourier transform ( ) jω eY which is
an approximation of a lowpass filter, and meets the specifications shown below in Table 1.
Passband Cutoff (ωp)
000,24
025,11 π
Passband Ripple ±0.1 dB or less
Stopband Frequency (ωs) 1.2ωp
Stopband Attenuation 70 dB or more
Phase Constraints |max grpdelay ‐ min grpdelay| ≤ 720 in the passband
Table 1
If your sampling rate conversion system functions properly, you should meet the specifications in Table
1, and when you play the output audio signal at 24,000 Hz, it should sound the same as the input audio
signal played at 11,025 Hz.
You should get a rough estimate of the efficiency of your design by determining how much computation
was required to perform the sampling rate conversion on the Wagner.wav signal. The method which
you will use to count the number of operations will be described shortly.
You are to write a MATLAB function srconvert such that the command srconvert(in) takes the
input signal in with an associated sampling rate of 11,025 Hz, and returns an output signal at a
sampling rate of 24,000 Hz. (See the section on writing MATLAB functions.)  Once your function
srconvert.m is finalized, run the command y=srconvert([1 zeros(1,3000)]);. This will
produce a vector y which contains the response of your system to a unit impulse. Then call
verify(y) to verify that your design meets the design specification.
The Files
The project zip file contains the audio files and MATLAB functions which you will need for this project.
To access the zip file, click on the link below where you found this file on the web site.
In testing your system, you may find it helpful to first use a unit impulse as input to your system and
then later try using real audio signals as inputs and listening to the outputs.  To load a sound file into a
vector x, type x=wavread(′filename.wav′);. To write a sound file for the MATLAB vector x into
the current directory, type wavwrite(x,sampfreq, ′filename.wav′). You may test your
system using any of the audio signals, although you should use the Wagner.wav signal to benchmark
your system performance.
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MATLAB Utilities
You may find the following MATLAB functions useful for your design.
examlpf(h, wp, vs) ‐ allows you to examine the passband ripple, the group delay, as well as the
stopband attenuation of the lowpass filter whose impulse response is h. It generates three
simultaneous plots. The first one zooms in on the passband with cutoff frequency wp. The
second plot measures the group delay in the passband, and the third plot is simply the
magnitude response over the entire frequency range (-π,π). The passband (wp) and stopband
(ws) cutoff frequencies are normalized by π/2. That is, a cutoff frequency at π/2 should be
entered as 0.5.
poly1(h, M) ‐ returns a matrix E whose i
th  row corresponds to the i
th  polyphase components of the
FIR filter h, obtained via type I decomposition with downsampling factor M.
fftfilt(h , x) ‐ convolves the signal x with the filter h using the FFTs. Beware that this command
might not always leads to a more efficient implementation than conv(h ,x), depending on
the length of the signals.
upsample(h ,L) ‐ returns an upsampled version of h by a factor L, without any interpolation.
downsample(h ,M) ‐ downsamples h by M.
Computation Counts
MATLAB does not automatically record the number of floating point operations (flops) in your algorithm, so
to measure your computational efficiency, you’ll have to determine the required number of multiplies and
adds yourself.  You can make this process somewhat automated by inserting a counter to be updated each
time the filter function is called, but you should also do a hand calculation to double check.
Do not include in the flops count the computation involved in designing any filters you need.
Example MATLAB Function
To give you an example of how to write a MATLAB function, here is the code from the file poly1.m.
function E=poly1(h,M)
%
% Performs type I polyphase decomposition of h in M components.
% The ith row of E corresponds to the ith polyphase component.
% Assumes that the first point of h is index 0.
%
h = [h zeros(1, ceil(length(h)/M)*M-length(h))];
E = reshape(h, M, length(h)/M);
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Tips
The old homework problem in the Appendix might be useful as a guideline to efficient implementation of an
interpolation filter. You may also find useful page 85 of the Vaidyanathan paper cited below.
P. P. Vaidyanathan, “Multirate digital filters, filter banks, polyphase networks, and applications: A
tutorial,” Proceedings of the IEEE, vol. 78, pp. 56‐92, Jan. 1990.
http://www.systems.caltech.edu/dsp/ppv/papers/ProcIEEEmultirateTUTExtra.pdf (Available 7/08)
Appendix – An Old Homework Problem:
x[ ] n ( ) c Let represent a signal which is obtained by sampling a continuous time audio signal x t
/ 44.1 kHz T
using an ideal C/D
converter shown in Figure A1. Assume that the sampling rate is 1 = .
Figure A1
We wish to design a 4x (4 times) oversampling digital FIR interpolation filter. One way to do this is to use the
single‐stage design of System 1 shown in Figure A2.
Figure A2:  System 1
The filter h n[ ] with Fourier transform )( j H e ω is designed using the window method with a Kaiser window.
Suppose the filter    h n[ ] is designed to meet Specification 1:
Specification 1:
1 1 ( )1 , j
j
H e ω
ω
2 H e( ) ,
δ δ ωω
δ ω ω π
− ≤ ≤+ ≤
≤ ≤ ≤
where 1 ω = 0.23π 2 , ω = 0.27π
4 , and δ 10− =
h n[ ]
.
(a) Using a Kaiser window, estimate the length of the filter   which meets Specification 1.
(b) Using the filter length estimate for   in part(a), estimate the number of multiplications per second
required in System 1 if the system is implemented in polyphase form using four polyphase components.
h n[ ]
An alternate way to design the 4x oversampling interpolation filter is to use the two‐stage design of System 2
shown in Figure A3.
x[ ] n
↑ 4
1 y n[ ]
h n[ ]
( ) x[ ] n c x t C/D
T
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Stage 1 Stage 2
2 y n[ ]
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)
Figure A3: System 2
The filters and   with frequency responses 1 h n[ ] 2 h n[ ] 1( j H e ω and 2 ( j H e ) ω , respectively, are designed using
the window method with Kaiser windows. Suppose that these filters are designed to meet Specification 2.
Specification 2:
1 1
1
2 1
2 1
2
1
1
( )1 , 2
() , 2
( )1 ,
() ,
j
j
j
H e
H e
H e
H e
ω
ω
ω
δ δω jω ω
δ ω ωπ
δ δω ω
δ πω ω π
′ ′ ≤ ≤+ ≤
≤ ≤ ′
′ ′ ≤ ≤+ ≤
≤ −≤ ′




where δ δ ′ = +− 1 1,ω1 , ω2 , and δ are given previously.
(c) Show that System 2 is equivalent to System 1 with
1 2 He H e H e ( ) ) ()( j jj ω ω ω
h n[ ]
j
=
2 (d) Show that if the filters and h [ ] n are designed using Kaiser windows to meet Specification 2, then
the resulting equivalent system in System 1 will have a filter
1
H e )( ω which meets Specification 1.  (You
may assume that the filters designed have magnitude responses which are monotonically decreasing in
the transition band from the passband to the stopband).
(e) Using Kaiser windows, estimate the lengths of the filters and h which meet Specification 2. 1 h n[ ] [ ] n
h n[ ] h n[ ]
2
(f) Using the filter length estimates for and in part (e), estimate the number of multiplications
per second required in System 2 if each stage is separately implemented in polyphase form using two
polyphase components. What are the computational savings in multiplications, if any, over System 1?
1 2
x[ ] n
↑ 2 1 h n[ ] 2 ↑ 2 h n[ ]

Project 1 Sampling Rate Conversion 
$30.00
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